Introduction and calculation of step-up transformer coil winding method
The low voltage coil of the step-up transformer should be thicker than the high voltage coil. In order to carry the corresponding current. The number of coils of the output voltage is larger than the number of coils input. In order to achieve boost. The boost ratio is calculated as the ratio of the two coil ratios. A qualified transformer is subject to scientific calculations. The boost ratio is calculated accurately. How large the silicon steel core is equipped with a thicker primary and secondary coil. It is fixed. The thickness of the coil is different depending on the boost ratio.
Its steps mainly include the assembly of transformers, the manufacture of coils, fuel tanks and accessories. Let us briefly talk about the winding method of high-frequency transformers in coil manufacturing:
1. Prepare materials first: skeleton, copper, enameled wire, high temperature tape, magnetic ring
Schematic diagram of transformer coil winding with the same name
L1 - K1 are the same name:
Example Interpretation of Step-Up Transformer Manufacturing Method
How to calculate the copper wire turns of the primary and secondary windings of the transformer! For example, how to calculate 220V into 12V! How to choose the size of silicon steel sheet! How to calculate the copper wire with a large diameter? Give you a reference and hope to help you:
Simple calculation of small transformers:
1, find the number of turns per volt, the number of turns per volt = 55 / core cross section, for example, your core section = 3.5 ╳ 1.6 = 5.6 square centimetres, therefore, the number of turns per volt = 55 / 5.6 = 9.8 åŒ
2, find the number of coil turns primary coil n1 = 220 ╳ 9.8 = 2156 åŒ secondary coil n2 = 8 ╳ 9.8 ╳ 1.05 = 82.32 is expected to be 82 åŒ secondary coil turns in the calculation of 1.05 is considered the load voltage drop
3, find the wire diameter You did not specify how much volts you want to output the current is how much? Here I assume 8V. The current is 2A. Transformer output capacity = 8 ╳ 2 = 16 volts input capacity of the transformer = transformer output capacity / 0.8 = 20 volts primary coil current I1 = 20 / 220 = 0.09 amp wire diameter d = 0.8 √ I primary coil wire diameter d1 =0.8√I1=0.8√0.09=0.24mm secondary coil wire diameter d2=0.8√I2=0.8√2=1.13 mm
The primary of a small power transformer is usually connected to 220 volts. Then:
1, the turns ratio: primary voltage / secondary voltage * 105% 100, that is 220 volts / secondary voltage * 105% 100;
2, the number of primary circle is determined: 40 to 50 divided by the core cross-sectional area (empirical formula), depending on the quality of the iron core, good iron core can take 40, poor iron core can take 50;
3, core cross-sectional area: S = 1.2 times the power / efficiency under the root number (efficiency: the efficiency of the transformer below 100VA is 60 to 95%);
4, copper wire cross-sectional area: according to the current calculation, generally take 2.5A per square millimeter. The primary current of the power transformer is power / 220 volts; the secondary current is power / secondary voltage.
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